10x^2+1000x-1200000=0

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Solution for 10x^2+1000x-1200000=0 equation:



10x^2+1000x-1200000=0
a = 10; b = 1000; c = -1200000;
Δ = b2-4ac
Δ = 10002-4·10·(-1200000)
Δ = 49000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49000000}=7000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-7000}{2*10}=\frac{-8000}{20} =-400 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+7000}{2*10}=\frac{6000}{20} =300 $

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